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18/07/2021 12:54 pm
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An electric bulb of resistance 20 Ω and a resistance wire of 4 Ω are connected in series with a 6 V battery.
Draw the circuit diagram and calculate :
(a) total resistance of the circuit.
(b) current through the circuit.
(c) potential difference across the electric bulb.
(d) potential difference across the resistance wire.
1 Answer
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18/07/2021 1:00 pm
(a) Total resistance of the circuit = R1 + R2
= 20 + 4 = 24 ohm
(b) We know that
V = IR
Therefore, 6 = I x 24
I = \(\frac{6}{24}\) = 0.25 amp
(c) p.d. across bulb = IR1
= 0.25 x 20 = 5V
(d) p.d. across resistance wire = IR2
= 0.25 x 4 = 1V