Notifications
Clear all
Electricity
1
Posts
2
Users
0
Likes
537
Views
0
19/07/2021 4:52 pm
Topic starter
A resistor of 8 ohms is connected in parallel with another resistor X. The resultant resistance of the combination is 4.8 ohms. What is the value of the resistor X?
1 Answer
0
19/07/2021 4:56 pm
A resistor of 8 ohm is connected in parallel with a resistor of X.
And resultant is 4.8.
Then X = ?
We know that for parallel case
\(\frac{1}{R}\) = \(\frac{1}{R_1}\) + \(\frac{1}{X}\)
\(\frac{1}{4.8}\) = \(\frac{1}{8}\) + \(\frac{1}{X}\)
\(\frac{1}{4.8}\) - \(\frac{1}{8}\) = \(\frac{1}{x}\)
After solving we get that
x = 12 ohms