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Sum of first three ionization energies of Al is 53.0 eV atom^–1 and the sum of first two ionization energies of Na is 52.2 eV atom^–1. Out of Al(III) and Na(II)
Classification of Elements and Periodicity in Properties
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23/08/2021 12:40 pm
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Sum of first three ionization energies of Al is 53.0 eV atom–1 and the sum of first two ionization energies of Na is 52.2 eV atom–1. Out of Al(III) and Na(II)
(a) Na (II) is more stable than Al (III)
(b) Al (III) is more stable than Na (II)
(c) Both are equally stable
(d) Both are equally unstable
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23/08/2021 12:41 pm
Correct answer: (b) Al (III) is more stable than Na (II)
Explanation:
Ionization energy is not the only the criteria for the stability of an oxidation state.
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