Notifications
Clear all
Ionization energies of atoms A and B are 400 and 300 k cal mol^–1 respectively. The electron affinities of these atoms are 80.0 and 85.0 k cal mol^–1 respectively.
Classification of Elements and Periodicity in Properties
1
Posts
2
Users
0
Likes
377
Views
0
20/08/2021 12:06 pm
Topic starter
Ionization energies of atoms A and B are 400 and 300 k cal mol–1 respectively. The electron affinities of these atoms are 80.0 and 85.0 k cal mol–1 respectively. Then which is the correct statement regarding electronegativity x?
(a) xA < xB
(b) xA > XB
(c) xA = xB
(d) none of these
Answer
Add a comment
Add a comment
Topic Tags
1 Answer
0
20/08/2021 12:10 pm
Correct answer: (b) xA > XB
Explanation:
Electronegativity of an atom = \(\frac{IE + EA}{2 \times 62.5}\)
where IE and EA are in k cal mol–1.
Add a comment
Add a comment
Forum Jump:
Related Topics
-
Consider the following ionisation reactions : I.E. (kJ mol^-1) - I.E. (kJ mol^–1) A(g) → A^+(g) + e^-, A1 A(g) →A^+(g) + e^-, A1
3 years ago
-
Which ionisation potential (IP) in the following equations involves the greatest amount of energy?
3 years ago
-
Which transition involves maximum amount of energy?
3 years ago
-
If the ionization enthalpy and electron gain enthalpy of an element are 275 and 86 kcal mol^-1 respectively
3 years ago
-
The basic character of MgO, BaO, Na2O and FeO follow the order
3 years ago
Topic Tags:
jee (1543)
,
jee main (999)
,
classification elements (78)
,
periodicity properties (78)
,
Forum Information
- 321 Forums
- 27.3 K Topics
- 53.8 K Posts
- 0 Online
- 12.4 K Members
Our newest member: Stripchat
Forum Icons:
Forum contains no unread posts
Forum contains unread posts
Topic Icons:
Not Replied
Replied
Active
Hot
Sticky
Unapproved
Solved
Private
Closed