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# Consider the following ionisation reactions : I.E. (kJ mol^-1) - I.E. (kJ mol^–1) A(g) → A^+(g) + e^-, A1 A(g) →A^+(g) + e^-, A1

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Consider the following ionisation reactions :

I.E. (kJ mol-1)     -        I.E. (kJ mol–1)

A(g) → A+(g) + e-, A1 A(g) →A+(g) + e-, A1

B+(g) → B2+(g) + e-, B2C(g) → C+(g) + e-, C1

C+(g) → C2+(g) + e-, C1C2+(g) → C3+(g) + e-, C3

If monovalent positive ion of A, divalent positive ion of B and trivalent positive ion of C have zero electron. Then incorrect order of corresponding I.E. is:

(a) C3 > B2 > A1

(b) B1 > A1 > C1

(c) C3 > C2 > B2

(d) B2 > C3 > A1

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Correct answer: (d) B2 > C3 > A1

Explanation:

A ⇒ H(1s1)

B ⇒ He(1s2)

C ⇒ Li(1s22s1)

A1 = IE1(A)  B2 = IE2 (B)

B1 = IE1(B)   C2 = IE2 (C)

C1 = IE1(C)  C3 = IE3 (C)

B1 > A1 > C1   C3 > B2 > A1

He > H > Li

Li2+ He+ H

1s2 1s1 2s1

1s1 1s1 1s1

C3 > C2 > B2

Li2+ Li+ He+

1s2 1s2 1s1

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