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Classification of Elements and Periodicity in Properties
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24/08/2021 11:16 am
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Aqueous solutions of two compounds M1 – O – H and M2 – O – H are prepared in two different beakers. If, the electronegativity of M1 = 3.4, M2 = 1.2, O = 3.5 and H = 2.1 then the nature of two solutions will be respectively :
(a) acidic, basic
(b) acidic, acidic
(c) basic, acidic
(d) basic, basic
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24/08/2021 11:19 am
Correct answer: (a) acidic, basic
Explanation:
The electronegativity difference between M1 and O is 0.1, which indicates M1– O bond will be covalent, since O–H bond having more ionic character thus bond will break and H+ ions gets release and acidic solution is formed and whereas difference between electronegativity of M2O is 2.3, thus, M2–OH bond will break. Hence, solution will be basic in nature.