The volume (in mL) of 0.1 N NaOH required to neutralise 10 mL of 0.1 N phosphinic acid is

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18/09/2020 12:32 pm

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aditi07

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The volume (in mL) of 0.1 N NaOH required to neutralise 10 mL of 0.1 N phosphinic acid is

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18/09/2020 12:38 pm

nikhil04

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Phosphinic acid is hypo phosphorous acid (H₃PO₂).

NaOH + H₃PO₂ → NaH₂PO₂ + H₂O

For neutrization

(N₁V₁)acid = (N₂V₂)base

= 0.1 x 10 = 0.1 x (V_mL)_NaOH

V_NaOH = 10 mL

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