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14/01/2022 3:25 pm
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The resistance of a conductivity cell with cell constant 1.14 cm-1, containing 0.001 M KCl at 298 K is 1500Ω. The molar conductivity of 0.001 M KCl solution at 298 K in S cm2 mol-1 is_______. (Integer answer)
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14/01/2022 3:29 pm
K = \(\frac{1}{R}\times \frac{\ell}{A}\)
= \(\Big(\Big(\frac{1}{1500}\Big) \times 1.14 \Big)\)S cm-1
⇒ Λm = 1000 x \(\frac{(\frac{1.14}{1500})}{0.001}\)S cm2 mol-1
= 760 S cm2 mol-1
= 760