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18/09/2020 10:36 am
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The mole fraction of glucose (C6H12O6) in an aqueous binary solution is 0.1. The mass percentage of water in it, to the nearest integer, is ………
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18/09/2020 10:39 am
Let total mole of solution = 1
so mole of glucose = 0.1
mole of H2O = 0.9
% (w/w) of H2O = [0.9 x 18/0.9 x 18 + 0.1 x 180] x 100
= 47.368
= 47.37