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30/01/2022 2:40 pm
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The molarity of the solution prepared by dissolving 6.3 g of oxalic acid (H2C2O4.2H2O) in 250 mL of water in mol L-1 is x × 10-2. The value of x is ________. (Nearest integer)
[Atomic mass : H : 1.0, C : 12.0, O : 16.0]
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30/01/2022 2:43 pm
(H2C2O4.2H2O) = \(\frac{weight/M_w}{V(L)}\)
⇒ x × 10-2 = \(\frac{\frac{6.3}{126}}{\frac{250}{1000}}\)
x = 20