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The elevation of boiling point of 0.10 m aqueous CrCl3.xNH3 solution is two times that of 0.05 m aqueous CaCl2 solution.

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The elevation of boiling point of 0.10 m aqueous CrCl3.xNH3 solution is two times that of 0.05 m aqueous CaCl2 solution. The value of x is …………..

[Assume 100% ionisation of the complex and CaCl2, coordination number of Cr as 6, and that all NH3 molecules are present inside the coordination sphere]

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0.05 m aqueous CaCl2 solution = 0.15 molal solution of non electrolyte.

Since the elevation in boiling point is double so the molality of given solution of complex = 0.3 m

Hence the complex must be producing three ions in the solution, so its formula = [Cr(NH3)5Cl]Cl2 so x = 5

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