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25/12/2021 12:58 pm
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Number of compounds which have greater freezing point than 0.1 M ethanol (Assume molarity = molality)
(a) 0.1 M Na2SO4
(b) 0.1 M Ba3(PO4)2
(c) 0.1 M HCl
(d) 0.1 M NaOH
1 Answer
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25/12/2021 1:04 pm
∆Tf = i Kf m
Since all solutions have the same concentration, ∆Tf will depend only on i.
i values are as follows:
Ethanol = 1
Na2SO4 = 3
Ba3(PO4)2 = 5
HCl = 2
NaOH = 2
Thus, all the given solutions will have more depression in freezing point than ethanol, i.e., they will have lesser freezing point than 0.1 M ethanol.