Notifications
Clear all
0
30/12/2021 1:50 pm
Topic starter
From 0.2 gm of a compound, 0.188 gm of AgBr is formed by Carius Method. Find % of Br?
(a) 80%
(b) 20%
(c) 40%
(d) 10%
1 Answer
0
30/12/2021 1:53 pm
Correct answer: (c) 40%
Explanation:
Molar mass of AgBr = (108 + 80) g/mol = 188 g/mol
188g of AgBr contains 80 g of Br
0.188 g of AgBr will contain \(\frac{80 \times 0.188}{188}\) g Br
In 0.2 g of compound % of Br = \(\frac{80 \times 0.188}{188 \times 0.2 } \times 100 \%\) = 40%