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30/01/2022 2:55 pm
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For a first order reaction, the ratio of the time for 75% completion of a reaction to the time for 50% completion is _______.
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30/01/2022 2:58 pm
k = \(\frac{2.303}{t}\)log \(\frac{a}{a - x}\)
= \(\frac{2.303}{t_{50 \%}}\) log \(\frac{100}{100 - 50}\)
= \(\frac{2.303}{t_{75 \%}}\) log \(\frac{100}{100 - 70}\)
t75% = 2t50%