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14/01/2022 4:02 pm
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Data given for the following reaction is as follows:
FeO(s) + C(graphite) → Fe(s) + CO(g)
Substance - ΔH°(kJ mol-1) - ΔS°(J mol-1 K-1)
FeO → -266.3 - 57.49
C(graphite) → 0 - 5.74
Fe(s) → 0 - 27.28
CO(g) → - 110.5 - 197.6
The minimum temperature in K at which the reaction becomes spontaneous is ________ .
1 Answer
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14/01/2022 4:12 pm
Tmin = \(\Big(\frac{\Delta^0H}{\Delta^0S}\Big)\)
Δ0Hrxn = [Δ0fH(Fe) + Δ0fH(CO)] - [Δ0fH(FeO) + Δ0fH(C(graphite))]
= [0 - 110.5] - [-266.3 + 0]
= 155.8 kJ/mol
Δ0Srxn = [Δ0S(Fe) + Δ0S(CO)] - [Δ0S(FeO) + Δ0S(C(graphite))]
= [27.28 + 197.6] – [57.49 + 5.74]
= 161.65 J/mol-K
Tmin = \(\frac{155.8 \times 10^3 J/mol}{161.65J/mol-K}\)
= 963.8 K
≃ 964 k