Considering that Δ0 > P, the magnetic moment (in BM) of [Ru(H2O)6]^2+ would be ……
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20/09/2020 11:24 am
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Considering that Δ0 > P, the magnetic moment (in BM) of [Ru(H2O)6]2+ would be ……
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20/09/2020 11:27 am
Ru2+ = 4d6 = t2g2,2,2eg0,0 since Δ0 > P
No. of unpaired electrons = zero
Magnetic Moment = 0
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