Considering that Δ0 > P, the magnetic moment (in BM) of [Ru(H2O)6]^2+ would be ……

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20/09/2020 11:24 am

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aditi07

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Considering that Δ₀ > P, the magnetic moment (in BM) of [Ru(H₂O)₆]²⁺ would be ……

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20/09/2020 11:27 am

nikhil04

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Ru²⁺ = 4d⁶ = t_2g^2,2,2eg^0,0 since Δ₀ > P

No. of unpaired electrons = zero

Magnetic Moment = 0

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