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Considering that Δ0 > P, the magnetic moment (in BM) of [Ru(H2O)6]^2+ would be ……

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Considering that Δ0 > P, the magnetic moment (in BM) of [Ru(H2O)6]2+ would be ……

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Ru2+ = 4d6 = t2g2,2,2eg0,0 since Δ0 > P

No. of unpaired electrons = zero

Magnetic Moment = 0

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