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18/09/2020 10:46 am
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An element with molar mass 2.7 × 10–2 kg mol–1 forms a cubic unit cell with edge length 405 pm. If its density is 2.7 × 103 kg m–3, the radius of the element is approximately ………. × 10–12 m (to the nearest integer)
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18/09/2020 10:50 am
d = Z x M/Na x Volume
2.7 = Z x 27/6.02 x 1023[4.05 x 10-3]3
Z = 4 => fcc unit cell
For fcc unit cell 4r = √2a
r = 1.414 x 405/4
= 143.1675 pm
= 143.17 pm