An element crystallises in a face–centred cubic (fcc) unit cell with cell edge a.
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20/09/2020 10:44 am
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An element crystallises in a face–centred cubic (fcc) unit cell with cell edge a. The distance between the centres of two nearest octahedral voids in the crystal lattice is :
(1) a/√2
(2) a
(3) a/2
(4) √2a
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20/09/2020 10:49 am
(1) a/√2
Explanation:
In FCC octahedral voids are present at the edge centers and body center.
Minimum distance between centers of two octahedral voids
= x = √{(a/2)2 + (a/2)2}
= √(a2/4 + a2/4)
= a/√2
This post was modified 4 years ago 2 times by nikhil04
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