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An element crystallises in a face–centred cubic (fcc) unit cell with cell edge a.

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An element crystallises in a face–centred cubic (fcc) unit cell with cell edge a. The distance between the centres of two nearest octahedral voids in the crystal lattice is :

(1) a/√2

(2) a

(3) a/2

(4) √2a

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(1) a/√2

Explanation:

In FCC octahedral voids are present at the edge centers and body center.

Minimum distance between centers of two octahedral voids

= x = √{(a/2)2 + (a/2)2}

= √(a2/4 + a2/4)

= a/√2

This post was modified 4 years ago 2 times by nikhil04
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