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30/12/2021 2:03 pm
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0.075 molal solution of sucrose solution containing 1 kg water is at the temperature of -0.4°C, If (Kf)H2O= 1.86 K/m. How much ice will freeze out?
(a) 350 g
(b) 100 g
(c) 180 g
(d) 650 g
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30/12/2021 2:07 pm
Correct answer: (d) 650 g
Explanation:
On freezing moles of sucrose does not change.
ΔTf = i × Kf × m
0.4 = \(\frac{1 \times 1.86 \times 0.075}{W_{H_2O} \times 1000}\) = 348.75 g
Amount of ice separated= (1000 - 348.75) g
Amount of ice separated = 651.25 ≈ 650 g