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# The following solutions were prepared by dissolving 10 g of glucose (C6H12O6) in 250 ml of water (P1), 10 g of urea (CH4N2O) in 250 ml of water (P2) and 10 g of sucrose (C12H22O11) in 250 ml of water (P3).

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The following solutions were prepared by dissolving 10 g of glucose (C6H12O6) in 250 ml of water (P1), 10 g of urea (CH4N2O) in 250 ml of water (P2) and 10 g of sucrose (C12H22O11) in 250 ml of water (P3). The right option for the decreasing order of osmotic pressure of these solutions is :

(1) P2 > P1 > P3

(2) P1 > P2 > P3

(3) P2 > P3 > P1

(4) P3 > P1 > P2

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Correct answer: (1) P2 > P1 > P3

Explanation:

π = iCRT

P1 = 1 x $$\frac{10}{180}$$ x R x T (For Glucose)

P2 = 1 x $$\frac{10}{60}$$ x R x T (For Urea)

P3 = 1 x $$\frac{10}{342}$$ x R x T (For Sucrose)

∴ P2 > P1 > P3

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