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21/09/2021 10:21 am
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The following solutions were prepared by dissolving 10 g of glucose (C6H12O6) in 250 ml of water (P1), 10 g of urea (CH4N2O) in 250 ml of water (P2) and 10 g of sucrose (C12H22O11) in 250 ml of water (P3). The right option for the decreasing order of osmotic pressure of these solutions is :
(1) P2 > P1 > P3
(2) P1 > P2 > P3
(3) P2 > P3 > P1
(4) P3 > P1 > P2
1 Answer
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21/09/2021 10:41 am
Correct answer: (1) P2 > P1 > P3
Explanation:
π = iCRT
P1 = 1 x \(\frac{10}{180}\) x R x T (For Glucose)
P2 = 1 x \(\frac{10}{60}\) x R x T (For Urea)
P3 = 1 x \(\frac{10}{342}\) x R x T (For Sucrose)
∴ P2 > P1 > P3