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22/09/2021 11:28 am
Topic starter
Match List-I with List-II
List-I - List-II
(a) [Fe(CN)6]3– → (i) 5.92 BM
(b) [Fe(H2O)6]3+ → (ii) 0 BM
(c) [Fe(CN)6]4– → (iii) 4.90 BM
(d) [Fe(H2O)6]2+ → (iv) 1.73 BM
Choose the correct answer from the options given below
(1) (a)-(iv), (b)-(ii), (c)-(i), (d)-(iii)
(2) (a)-(ii), (b)-(iv), (c)-(iii), (d)-(i)
(3) (a)-(i), (b)-(iii), (c)-(iv), (d)-(ii)
(4) (a)-(iv), (b)-(i), (c)-(ii), (d)-(iii)
1 Answer
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22/09/2021 11:32 am
Correct answer: (4) (a)-(iv), (b)-(i), (c)-(ii), (d)-(iii)
Explanation:
[Fe(CN)6]3– → Fe+3 = 3d5
Unpaired electrons = 4, µ = 4.9 BM