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Match List-I with List-II List-I - List-II (a) [Fe(CN)6]^3– → (i) 5.92 BM (b) [Fe(H2O)6]^3+ → (ii) 0 BM

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Match List-I with List-II

List-I          -       List-II

(a) [Fe(CN)6]3– → (i) 5.92 BM

(b) [Fe(H2O)6]3+ → (ii) 0 BM

(c) [Fe(CN)6]4– → (iii) 4.90 BM

(d) [Fe(H2O)6]2+ → (iv) 1.73 BM

Choose the correct answer from the options given below

(1) (a)-(iv), (b)-(ii), (c)-(i), (d)-(iii)

(2) (a)-(ii), (b)-(iv), (c)-(iii), (d)-(i)

(3) (a)-(i), (b)-(iii), (c)-(iv), (d)-(ii)

(4) (a)-(iv), (b)-(i), (c)-(ii), (d)-(iii)

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Correct answer: (4) (a)-(iv), (b)-(i), (c)-(ii), (d)-(iii)

Explanation:

[Fe(CN)6]3– → Fe+3 = 3d5

Unpaired electrons = 4, µ = 4.9 BM
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