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Chemical Bonding and Molecular Structure
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01/09/2021 11:32 am
Topic starter
The group of molecules having identical shape is :
(a) PCl5, IF5, XeO2F2
(b) BF3, PCl3, XeO3
(c) SF4, XeF4, CCl4
(d) ClF3, XeOF2, XeF3+
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01/09/2021 11:36 am
Correct answer: (d) ClF3, XeOF2, XeF3+
Explanation:
ClF3 → Hybridisation
= 3 + \(\frac{1}{2}\)[7 - 3] = 5(sp3d)
XeOF2 → Hybridisation
= 3 + \(\frac{1}{2}\)[8 - 4] = 5(sp3d)
XeF3+ → Hybridisation
= 3 + \(\frac{1}{2}\)[8 - 3 - 1] = 5(sp3d)
All molecules have sp3d hybridization and 2 lone pairs. Hence all have identical (T-shape).