The dipole moments of diatomic molecules AB and CD are 10.41D and 10.27 D, respectively while their bond distances are 2.82 and 2.67 Å, respectively. This indicates that
(a) bonding is 100% ionic in both the molecules
(b) AB has more ionic bond character than CD
(c) AB has lesser ionic bond character than CD
(d) bonding is nearly covalent in both the molecules
Correct answer: (c) AB has lesser ionic bond character than CD
Explanation:
As dipole moment = electric charge × bond length
D. M. of AB molecule
= 4.8 x 10-10 x 2.82 x 10-8 = 13.53D
D.M. of CD molecule
= 4.8 x 10-10 x 2.67 x 10-8 = 12.8 D
Now % ionic character
= \(\frac{Actual\;dipole\;moment\;of\;the\;bond}{Dipole\;moment\;of\;pure\;ionic\;compound}\) x 100
then % ionic character in AB
= \(\frac{10.41}{13.53}\) x 100 = 76.94%
% ionic character in CD
= \(\frac{10.27}{12.81}\) x 100 = 80.17%