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The correct order of bond dissociation energy among N2, O2, O2^- is shown in which of the following arrangements?

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The correct order of bond dissociation energy among N2, O2, O2- is shown in which of the following arrangements?

(a) N2 > O2- > O2

(b) O2- > O2 > N2

(c) N2 > O2 > O2-

(d) O2 > O2- > N2

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Correct answer:(c) N> O> O2-

Explanation:

The bond order of N2, O2, and O2- are respectively 3, 2 and 1.5.

Since higher bond order implies higher bond dissociation energy hence the correct order will be N> O> O2-

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