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SF2, SF4 and SF6 have the hybridisation at sulphur atom respectively as:

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SF2, SF4 and SF6 have the hybridisation at sulphur atom respectively as:

(a) sp2, sp3, sp2d2

(b) sp3, sp3, sp3d2

(c) sp3, sp3d, sp3d2

(d) sp3, spd2, d2sp3

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Correct answer: (c) sp3, sp3d, sp3d2

Explanation:

Hybridisation :

1. :SF2 ⇒ \(\frac{1}{2}\)(6 + 2) = 4 = sp3

2. :SF4 ⇒ \(\frac{1}{2}\)(6 + 4) = 5 = sp3d

3. SF6 ⇒ \(\frac{1}{2}\)(6 + 6) = 6 = sp3d2

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