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Chemical Bonding and Molecular Structure
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30/08/2021 10:13 am
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Dipole moment of H2O is 1.85 D. If the bond angle is 105° and O — H bond length is 0.94 Å, what is the magnitude of charge on the oxygen atom in water molecule?
(a) 2 × 10–10 esu
(b) 4.28 × 10–10 esu
(c) 3.22 × 10–10 esu
(d) 1.602 × 10–19 C
1 Answer
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30/08/2021 10:16 am
Answer is (c) 3.22 × 10–10 esu
Explanation:
μ = 1.85 D = 1.85 × 10–18 esu cm = q × d
cos 52.5° = \(\frac{d}{0.94Å}\)
⇒ d = 0.609 x 0.94Å
= 0.572Å
∴ μ = q x d
q1 = \(\frac{μ}{d}\)
= \(\frac{1.85 D}{0.572Å}\)
= \(\frac{1.85 \times 10^{18}esu\;cm}{0.572 \times 10^{-8} cm}\)
= 3.22 × 10–10 esu
This post was modified 3 years ago 2 times by Shivani siva
This post was modified 3 years ago by admin